Example 5 :
Complete the following table so that * is commutative binary operation on the set S = {a,b,c,d}.
From the table, there is no identity and inverse element.(G1 and G2 are not satisfied).
Therefore, it is not a group.
Friday, August 13, 2010
GROUPS 6
Thursday, August 12, 2010
GROUPS 5
Finite Groups and Group Tables
Finite group - Group where the set G has finite element.
The rules :
Finite group - Group where the set G has finite element.
The rules :
- List the identity first (use definition G2).
- To find an inverse elements for each element e, a (use definition G3) a' must be either a or e.
- All axioms are satisfied except possibly the associative property. Checking associativity on a case by case basis.
GROUPS 4
Theorem 3 ( The uniqueness of identity & inverse elements in G )
In a group G with binary operation *, there is only one element e in G such that
In a group G with binary operation *, there is only one element e in G such that
e*x = x*e = x
for all x in G.
Likewise, for each a in G, there is only one element a' in G that
Likewise, for each a in G, there is only one element a' in G that
a'*a = a*a' = e
In summary, the identity & inverse of each element are unique in a group.
GROUPS 3
Elementary Properties of Groups
Theorem 1 (Left & Right Cancellation Laws)
If G is a group with binary operation *, then the left and right cancellation laws hold in G, that is
Theorem 1 (Left & Right Cancellation Laws)
If G is a group with binary operation *, then the left and right cancellation laws hold in G, that is
a*b = a*c implies b = c, and
b*a = c*a implies b = c for all a,b,c in G
Similarly, we can prove the right cancellation law.
b*a = c*a implies b = c for all a,b,c in G
Proof:
(To prove the left cancellation law)
To show if a*b = a*c then b = c
Let a*b = a*c
Since G is a group, G3 is satisfied. Then, for all a' in G such that,
(To prove the left cancellation law)
To show if a*b = a*c then b = c
Let a*b = a*c
Since G is a group, G3 is satisfied. Then, for all a' in G such that,
a'*(a*b) = a'*(a*c) --G3
(a'*a)*b = (a'*a)*c --G1,* associative
e*b = e*c --by def. of a' in G3
b = c
(a'*a)*b = (a'*a)*c --G1,* associative
e*b = e*c --by def. of a' in G3
b = c
Similarly, we can prove the right cancellation law.
GROUPS 2
Example 3 :
Let G = {x element of G|x is not equal to 1}. On G, define * by a*b = a+b-ab. Determine whether the set G is a group under *.
G1 : (To show associativity of *)
Let a, b, c element of G & a,b, c is not equal to 1.
(a*b)*c = a*(b*c)
Let G = {x element of G|x is not equal to 1}. On G, define * by a*b = a+b-ab. Determine whether the set G is a group under *.
G1 : (To show associativity of *)
Let a, b, c element of G & a,b, c is not equal to 1.
(a*b)*c = a*(b*c)
GROUPS
Definition 1 (Group)
A group is a binary operation structure (G,*) is a nonempty set and * is a binary operation on G such that the following axioms are satisfied.
G1 : For all a, b, c in G,
G2 : There is an element e in G such that for all x in G,
G3 : Corresponding to each a in G, there ia an element a' in G such that
A group is a binary operation structure (G,*) is a nonempty set and * is a binary operation on G such that the following axioms are satisfied.
G1 : For all a, b, c in G,
(a*b)*c = a*(b*c)
Associativity of *
Associativity of *
G2 : There is an element e in G such that for all x in G,
e*x = x*e = x
Identity of *
Identity of *
G3 : Corresponding to each a in G, there ia an element a' in G such that
a*a' = a'*a = e
Inverse a' of a
Inverse a' of a
Note : If any of these axioms is not satisfied, then a binary structure is not a group.
BINARY OPERATIONS 4
sources :http://www.youtube.com/user/videomathtutor#p/a
Theorem 1 ( Uniqueness of Identity Element )
A binary structure (S,*)
To prove "uniqueness"
- suppose two different elements to be the element that we want to prove unique.
- finally, to show these two elements are actually same.
(To show the identity element in (S,*) is unique).
Let e & f be identity element of S
Then,
Since e is the identity element
e*f = f*e = f ----1
Also, since f is the identity element
e*f = f*e = e ----2
Hence,
from 1 & 2 f = e
Therefore, the identity element in (S,*) must be unique.
Wednesday, August 11, 2010
BINARY OPERATIONS 3
sources : http://www.learningupgrade.com
Some important words:
Not everywhere define - Operation * is called not everywhere defined on S it - no element can be assigned to each possible ordered pairs.
Not well defined - Operation * is called not well defined on S it - several element of S are assigned to S (ambiguity).
BINARY OPERATIONS 2
Definition 3 (Commutative operation)
A binary operation * on a set S is commutative if a*b = b*a for all a, b in S.
Example 1 :
On Q, define a binary operation * by a*b = ab + 1. Show that the binary operation * is commutative on Q.
Let a, b element of Q,
(To check whether a*b = b*a)
LHS : a*b
= ab+1
= ba+1 since multiplication is commutative on Q.
= b*a = RHS
Therefore, * is commutative on Q.
Example 2 :
On Z, define a*b = a-b. Determine whether * is commutative on Z.
Let a, b element of Z
To check whether a*b = b*a
Note that,
by using counter example
let 1, 2 in Z.
LHS : 1 - 2 = -1
RHS : 2 - 1 = 1
but, since LHS is not equal to RHS, then * is not commutative on Z.
A binary operation * on a set S is commutative if a*b = b*a for all a, b in S.
Example 1 :
On Q, define a binary operation * by a*b = ab + 1. Show that the binary operation * is commutative on Q.
Let a, b element of Q,
(To check whether a*b = b*a)
LHS : a*b
= ab+1
= ba+1 since multiplication is commutative on Q.
= b*a = RHS
Therefore, * is commutative on Q.
Example 2 :
On Z, define a*b = a-b. Determine whether * is commutative on Z.
Let a, b element of Z
To check whether a*b = b*a
Note that,
by using counter example
let 1, 2 in Z.
LHS : 1 - 2 = -1
RHS : 2 - 1 = 1
but, since LHS is not equal to RHS, then * is not commutative on Z.
BINARY OPERATIONS
Definition 1 ( Binary Operations)
Let S a nonempty set. A binary operation on S is a function from S x S into S. Let * be a binary operation on S. For each a,b element of S, we denote.
Let S a nonempty set. A binary operation on S is a function from S x S into S. Let * be a binary operation on S. For each a,b element of S, we denote.
the element *((a,b)) of S by (a*b).
An operation is called binary operation on S if :
On Z, with operation addition (+).
3 is assigned to (2, 1)
-1 is assigned to (0, -1)
Hence, condition 1 satisfied.
Also, for each ordered pair of elements of Z, the element assigned to it is again in Z.
Hence, condition 2 is satisfied.
Note : Since Z with operation + satisfied condition 2, we say Z is closed under addition.
- Exactly one element is assigned to each possible ordered pair of element S.
- For each ordered of element of S, the element assigned to again in S.
On Z, with operation addition (+).
3 is assigned to (2, 1)
-1 is assigned to (0, -1)
Hence, condition 1 satisfied.
Also, for each ordered pair of elements of Z, the element assigned to it is again in Z.
Hence, condition 2 is satisfied.
Note : Since Z with operation + satisfied condition 2, we say Z is closed under addition.
RELATIONS
Definition 1 (Cartesian Product)
Let A & B be sets. The set A x B = {(a,b) | a element af A, b element of B} is the Cartesian product of A & B.
Definition 2 (Relation)
A relation between sets A & B is a subset R of A x B. We read aRb as "a is related to b".
Example (Equality Relation) :
The equality relation "=" defined on a set by = is the subset { (x,x) | x element of S} of S xS
Thus, for any X element of S, we have x = x
But, if x and y are different element of S, then (x,y) are not same.
Definition 3 (Partition)
A partition of a set is a collection of nonempty susets of S such that every element of S is in exactly one of the subsets.
The subsets are the cells of the partition.
Let A & B be sets. The set A x B = {(a,b) | a element af A, b element of B} is the Cartesian product of A & B.
Definition 2 (Relation)
A relation between sets A & B is a subset R of A x B. We read aRb as "a is related to b".
Example (Equality Relation) :
The equality relation "=" defined on a set by = is the subset { (x,x) | x element of S} of S xS
Thus, for any X element of S, we have x = x
But, if x and y are different element of S, then (x,y) are not same.
Definition 3 (Partition)
A partition of a set is a collection of nonempty susets of S such that every element of S is in exactly one of the subsets.
The subsets are the cells of the partition.
SETS
LOGIC & PROOF
- Logic is the study of reasoning.
- Logic examines general forms which arguments may take, which forms are valid, and which are fallacies.
- Two parts of logic :
Inductive reasoning - give general conclusion from specific example.
Deductive reasoning - give logical conclusion from definitions and axioms.
- In mathematics, a proof is a convincing demonstration that some mathematical statement is necessarily true.
- Also, proof is a sequence of inferences that starts with the axioms, and leads to the particular statement you wish to prove.
- A proof must demonstrate that a statement is true in all cases, without a single exception.
- Some terms :
Theorem - The statement that is proved.
Lemma - The statement which use as a stepping stone in the proof of another theorem.
Monday, August 9, 2010
PRELIMINARIES
Algebra provides a generalization of arithmetic by using symbols, usually letters, to represent numbers.
For example, it is obviously true that
2 + 3 = 3 + 2
This arithmetic statement can be generalized using algebra to
x + y = y + x
where x and y can be any number.
*Algebra has been studied for many centuries.
HISTORY OF ALGEBRA
Egyption & Babylonian Algebra
For example, it is obviously true that
2 + 3 = 3 + 2
This arithmetic statement can be generalized using algebra to
x + y = y + x
where x and y can be any number.
*Algebra has been studied for many centuries.
HISTORY OF ALGEBRA
Egyption & Babylonian Algebra