A group is a binary operation structure (G,*) is a nonempty set and * is a binary operation on G such that the following axioms are satisfied.
G1 : For all a, b, c in G,
(a*b)*c = a*(b*c)
Associativity of *
Associativity of *
G2 : There is an element e in G such that for all x in G,
e*x = x*e = x
Identity of *
Identity of *
G3 : Corresponding to each a in G, there ia an element a' in G such that
a*a' = a'*a = e
Inverse a' of a
Inverse a' of a
Note : If any of these axioms is not satisfied, then a binary structure is not a group.
Example 1:
(Z,+) is a group because it satisfies G1, G2, G3. That is,
G1 : for all a, b, c in Z
G2 : Since 0+a = a+0 = a for all a in Z then, 0 is the identity for (Z,+).
G3 : For each a in Z, exist an element a' = -a element of Z such that a+(-a) = 0 = (-a)+a. Then, -a is the inverse element of a in (Z,+).
Example 2 :
Let * be defined on Q+ by a*b = ab/2
Show that the binary structure (Q+,*) is a group.
Solution :
G1 : (To show associativity of *)
Let a, b, c be element of Q+
LHS:
(a*b)*c
= (ab/2)*c
= (ab/2)c / 2
= (ab)c/4
= a(bc)/4 multiplication is associative on Q+.
= a(bc/2) / 2
= a(bc)/2
= a*(b*c)
= RHS
Since, LHS = RHS then, * is associative on Q+.
G2 : Let a in Q+.
(To find (b = e) element of Q+ such that a*b = b*a = a)
LHS : a*b = ab/2 = a --- b = 2 element of Q+
RHS : b*a = ba/2 = a --- b = 2 element of Q+
Then, b = e = 2 is the identity element of (Q+,*).
G3 : (To find the inverse element of (Q+,*))
LHS : a' = 4/a element of Q+.
RHS : a' = 4/a element of Q+.
Then, b = a' = 4/a is the inverse element of (Q+,*).
Therefore, (Q+,*) is a group.
Example 1:
(Z,+) is a group because it satisfies G1, G2, G3. That is,
G1 : for all a, b, c in Z
(a+b)+c = a+(b+c)
G2 : Since 0+a = a+0 = a for all a in Z then, 0 is the identity for (Z,+).
G3 : For each a in Z, exist an element a' = -a element of Z such that a+(-a) = 0 = (-a)+a. Then, -a is the inverse element of a in (Z,+).
Example 2 :
Let * be defined on Q+ by a*b = ab/2
Show that the binary structure (Q+,*) is a group.
Solution :
G1 : (To show associativity of *)
Let a, b, c be element of Q+
LHS:
(a*b)*c
= (ab/2)*c
= (ab/2)c / 2
= (ab)c/4
= a(bc)/4 multiplication is associative on Q+.
= a(bc/2) / 2
= a(bc)/2
= a*(b*c)
= RHS
Since, LHS = RHS then, * is associative on Q+.
G2 : Let a in Q+.
(To find (b = e) element of Q+ such that a*b = b*a = a)
LHS : a*b = ab/2 = a --- b = 2 element of Q+
RHS : b*a = ba/2 = a --- b = 2 element of Q+
Then, b = e = 2 is the identity element of (Q+,*).
G3 : (To find the inverse element of (Q+,*))
LHS : a' = 4/a element of Q+.
RHS : a' = 4/a element of Q+.
Then, b = a' = 4/a is the inverse element of (Q+,*).
Therefore, (Q+,*) is a group.
sources : http://www.youtube.com/user/singingbanana
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