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Some important words:
Not everywhere define - Operation * is called not everywhere defined on S it - no element can be assigned to each possible ordered pairs.
Not well defined - Operation * is called not well defined on S it - several element of S are assigned to S (ambiguity).
Definition 5 ( Binary Algebraic Structure)
A binary algebraic structure, denoted by (S,*)
Example : (Z,*) , (Q,*)
Definition 6 (Identity element for *)
Let (S,*)
e*s = s*e = s.
Example 1 :
- 0 is identity for + (addition) on R. Since
0+a = a+0 = a for all a in R.
- 1 is identity for . (multiplication) on R. Since
1.a = a.1 = a for all a in R.
Example 2 :
Determine the identity of (Q,*) where * is defined by a*b = ab/2.
Solution :
Let a, b element of Q
LHS :
Since LHS = RHS and 2 is element of Q, then b = 2 is identity of (Q,*).
Example 3 :
Determine whether (Z,*) , where * is defined by a*b = a-b+1, has an identity.
Solution :
Since LHS and RHS is not equivalent, therefore, there is no identity for (Z,*) .
Example 2 :
Determine the identity of (Q,*) where * is defined by a*b = ab/2.
Solution :
Let a, b element of Q
LHS :
a*b = a
ab/2 = aab = 2a
b = 2 element of Q
b = 2 element of Q
RHS :
b*a = a
ba/2 = a
ba = 2a
b = 2 element of Q
b*a = a
ba/2 = a
ba = 2a
b = 2 element of Q
Since LHS = RHS and 2 is element of Q, then b = 2 is identity of (Q,*).
Example 3 :
Determine whether (Z,*)
Solution :
LHS :
a*b = a
a-b+1 = a
-b+1 = 0
b = 1 element of Z
a*b = a
a-b+1 = a
-b+1 = 0
b = 1 element of Z
RHS :
b*a = a
b-a+1 = a
b+1 = 2a
b = 2a-1 element of Z
b*a = a
b-a+1 = a
b+1 = 2a
b = 2a-1 element of Z
Since LHS and RHS is not equivalent, therefore, there is no identity for (Z,*)
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